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What is the maximum area for a rectangle with an perimeter of 108 meters?
Wiki User
∙ 11y ago
By using Differential Calculus.
Any rectangle is at a maximum area when it is a square.
So taking 108 and dividing by '4'
We have '27' This is the length of one side of the square
So its areis
A(sq) = 27^2 = 729 m^2
lenpollock
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