To find mean, you add up all of your data and then divide by how many numbers there are. Mean is the same thing as average.

1+3+5+7+9 = 25

25 divided by 5 (the number of numbers) equals 5. The average or mean of this set of data is 5.

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4

3

Several solutions. 17 + 1 + 1 + 1 + 1 15 + 3 + 1 + 1 + 1 13 + 5 + 1 + 1 + 1, 13 + 3 + 3 + 1 + 1 11 + 7 + 1 + 1 + 1, 11 + 5 + 3 + 1 + 1, 11 + 3 + 3 + 3 + 1 9 + 9 + 1 + 1 + 1, 9 + 7 + 3 + 1 + 1, 9 + 5 + 5 + 1 + 1, 9 + 5 + 3 + 3 + 1 7 + 7 + 5 + 1 + 1, 7 + 7 + 3 + 3 + 1, 7 + 5 + 5 + 3 + 1, 7 + 5 + 3 + 3 + 3 5 + 5 + 5 + 5 + 1 Note that there is only one solution that does not include 1, namely 7 + 5 + 3 + 3 + 3

The mean of the numbers 3 5 7 is 5.

they are both 5

{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}

With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.

0.6

Mean: 7 Median: 6 Mode: 1, 9, 4, 7, 5, 3, 16, 11

if you mean (x-5)/6=1/3 then x=7 but if you mean x-(5/6)=1/3 then x=1 1/6 or 7/6

{ [(1+3) *5 ] +7 } /9 = 3 [4 *5] + 7 = 27 divided by 9 = 3 also [ (1+3) / (5+7) ] * 9 = 3 More complex is 13 * (5+7) - 9 = 3 with just signs : -1 -3 +5 -7 + 9 = 3

If by "smaller than ten" you mean closer to zero than 10, then sum = -9 + -7 + ... + -1 + 1 + ... + 7 + 9 = 0 If you mean the numbers less than 10, then: sum = 9 + 7 + ... + 1 + -1 + -3 + ... = -∞ If you mean the counting numbers less than 10, then: sum = 1 + 3 + 5 + 7 + 9 = ½ × 5 × (1 + 9) = ½ × 5 × 10 = 25

1. Find the arithmetic mean (average)2. Find the distance of each number from the mean (x-the mean=?)3. Square each number4. Add up all of the squares5. Divide the final sum by the original meanEX: Set: 1, 3, 4, 5, 71. 1 + 3 + 4 + 5 + 7 = 20 / 5 = 42. 1-4=-3 3-4=-1 4-4=0 5-4=17-4=33. 3*3=9 1*1=1 0*0=0 1*1=13*3=94. 9 + 1 + 0 + 1 + 9 = 205. 20 / 4 = 5

3 = 1 x 3 5 = 1 x 5 7 = 1 x 7 GCF = 1

Odd numbers are integers (whole numbers) that are not divisible by 2: 1, 3, 5, 7, ..., -1, -3, -5, -7...Odd numbers are integers (whole numbers) that are not divisible by 2: 1, 3, 5, 7, ..., -1, -3, -5, -7...Odd numbers are integers (whole numbers) that are not divisible by 2: 1, 3, 5, 7, ..., -1, -3, -5, -7...Odd numbers are integers (whole numbers) that are not divisible by 2: 1, 3, 5, 7, ..., -1, -3, -5, -7...

4 × 3/7 = 4/1 × 3/7 = (4×3)/(1×7) = 12/7 = (1×7+5)/7 = 1 5/7

5 + 3 + 7 + 3 + 2 = 20/5 = 4 The mean of the numbers is 4.

The domain of 1 3 5 5 7 7 can not be given because it is not a function.

420 3 = 3*1 4 = 2*2 5 = 5*1 6 = 2*3 7 = 7*1 1*3*2*2*5*7 = 420 From ....

Modulus. 7%5 is 2, 7%4 is 3, 7%3 is 1.

The average or mean of 3, 5, 7, 9, and 11 is 7.

To find the mean, you add all of the numbers and divide by how many numbers you added together. 7+2+3+2+1=15. 15/5=3. The mean is 3.

Example: 1 + 3/5 = ? Step 1: make the denominators the same: 1 = 5/5 Step 2: put the 5/5 into the problem in place of the 1: 1 + 3/5 = 5/5 +3/5 Step 3: add the numerators: 5/5 + 3/5 = 8/5 Example 2: 3 + 6/7 = ? 3 = (3x7)/7 = 21/7 21/7 + 6/7 = 27/7

(1/3)/(7/15) = 1/(7/5) = 5/7

3+6=9 9-6=3 3+2=5 5+2=7 7-6=1 Heres where it repeats 1+6=7 7-6=1 1+2=3 Answer is 3