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To find mean, you add up all of your data and then divide by how many numbers there are. Mean is the same thing as average.

1+3+5+7+9 = 25

25 divided by 5 (the number of numbers) equals 5. The average or mean of this set of data is 5.

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โˆ™ 2011-02-08 22:44:02
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A polynomial of degree zero is a constant term

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โˆ™ 2020-06-15 10:06:32

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Q: What is the mean of 1 3 5 7 9?
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Related questions

What is the mean for the numbers 1 5 5 7 3 3 and 4?

4


What is the mean of 3 1 7 0 5 2?

3


What are the mean and media of 1 3 5 7 9?

they are both 5


The mean of the numbers 3 5 7?

The mean of the numbers 3 5 7 is 5.


What five odd numbers add up to twenty-one?

Several solutions. 17 + 1 + 1 + 1 + 1 15 + 3 + 1 + 1 + 1 13 + 5 + 1 + 1 + 1, 13 + 3 + 3 + 1 + 1 11 + 7 + 1 + 1 + 1, 11 + 5 + 3 + 1 + 1, 11 + 3 + 3 + 3 + 1 9 + 9 + 1 + 1 + 1, 9 + 7 + 3 + 1 + 1, 9 + 5 + 5 + 1 + 1, 9 + 5 + 3 + 3 + 1 7 + 7 + 5 + 1 + 1, 7 + 7 + 3 + 3 + 1, 7 + 5 + 5 + 3 + 1, 7 + 5 + 3 + 3 + 3 5 + 5 + 5 + 5 + 1 Note that there is only one solution that does not include 1, namely 7 + 5 + 3 + 3 + 3


The mean of numbers 1 3 5 7 9 is?

Mean means average, therefore it is 5.


What is The set of all odd natural numbers less than 9 is?

{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}


What is 3 sevenths divided by 5?

0.6


What is the mean median and mode for 1 9 4 7 5 3 16 11?

Mean: 7 Median: 6 Mode: 1, 9, 4, 7, 5, 3, 16, 11


2 variable x minus 5 over 6 equal 1 third?

if you mean (x-5)/6=1/3 then x=7 but if you mean x-(5/6)=1/3 then x=1 1/6 or 7/6


How do you find mode if mean and median is given?

With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.


What is the gcf of 3 5 7?

3 = 1 x 3 5 = 1 x 5 7 = 1 x 7 GCF = 1

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