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What is the slope of the line that passes through (51) and (2-7)?
Wiki User
∙ 9y ago
If you mean points of (5, 1) and (2, -7) then the slope works out as 8/3
Wiki User
∙ 9y ago
Wiki User
∙ 9y agoAssuming the points are (5, 1) and (2, -7), the slope is [1 - (-7)]/[5 - 2] = 8/3.
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What is the equation of the line that passes through the point -7-3 and is parallel to -5x plus 8y equals 27?
Put the equation of the given line into slope-intercept form. The slope is then the coefficient of x. -5x + 8y = 27. 8y = 5x + 27 y = 5/8 x + 33/8.........so the slope of a parallel line is the same i.e. 5/8 Now use the standard slope-intercept equation , y = mx + c, where m is the slope and c is the y-intercept. Substituting the ordered pair values for x and y, and as m is known - this gives, -3 = 5/8(-7) + c : -3 = -43/8 + c : c = 13/8 The equation of the parallel line is thus, y = 5/8x + 13/8 and multiplying throughout by 8 produces an equivalent equation, 8y = 5x + 11
What is the equation of the line containing the points (0, 0), (-3, -9), and (9, 27)?
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x
What is the slope of the line that contains the points -27 and 23?
If you mean points (x,y) : (-2, 7) and (2, 3) then the slope works out as -1 as the slope = (y2-y1)/(x2-x1) = (3-7)/(2 +2) = -4/4 = -1
What number is equal to -27?
-27 is a number. Through the Reflexive Property of Algebra, -27=-27. You could also represent it as an expression such as 0-27 or -28+1.
Which points are 24 units from the point located at 51 on a number line?
27 and 75
Can the slope of a line be a fraction?
Of course. If the line rises 18 units for every 27 horizontal units,then its slope is 2/3 .
What is the slope of the line containing point (27) and (44)?
Points: (2, 7) and (4, 4) Slope: -3/2
What is the equation of the line that passes through the point -7-3 and is parallel to -5x plus 8y equals 27?
Put the equation of the given line into slope-intercept form. The slope is then the coefficient of x. -5x + 8y = 27. 8y = 5x + 27 y = 5/8 x + 33/8.........so the slope of a parallel line is the same i.e. 5/8 Now use the standard slope-intercept equation , y = mx + c, where m is the slope and c is the y-intercept. Substituting the ordered pair values for x and y, and as m is known - this gives, -3 = 5/8(-7) + c : -3 = -43/8 + c : c = 13/8 The equation of the parallel line is thus, y = 5/8x + 13/8 and multiplying throughout by 8 produces an equivalent equation, 8y = 5x + 11
What is the slope of the line given by the equation y5x-22?
27
What is the point-slope equation of a line with slope -4 that contains the point (-27)?
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
How can you graph 3x-9y equals 27?
3x - 9y = 27-9y = -3x + 279y = 3x - 27y = x/3 - 3The graph is a straight line, with (slope = 3), and passing through the point (y = - 3) on the y-axis.
What is the slope of the line between the points (-327) and (-279)?
If you mean points of: (-3, 27) and (-2, 79) then it works out as 52 Any other arrangements of the points will give a different slope.
Using the point slope formula what is the answer if the line pass through 0-9and-9-6?
Point-slope formula is y-y1=m(x-x1) The problem looks like: y-(-9)=-1/3(x-0) In Standard Form(answer): x+3y=-27
What is the equation for a line that goes through points -4 16 and 2 -11?
(-4, 16), (2, -11)First, find the slope of the line.m = (y2 - y1)/(x2 - x1) = [16 - (-11)]/(-4 - 2) = 27/-6 = -27/6Use the point-slope form of the equation of the line with m = -27/6, x1 = 2 and y1 = -11.((y - y1) =m(x - x1) substitute;y - (-11) = -(27/6)(x - 2)y + 11 = -(27/6)x + 54/6y + 11 - 11 = -(27/6)x + 9 - 11y = -(27/6)x - 3 This is the slope-intercept form of the equation of the line.The general form of the equation of the line is: Ax + By + C = 0 where A, B, and C are real numbers, and A and B are not both zero.So, you have:y = -(27/6)x - 3y + (27/6)x + 3 = -(27/6)x + (27/6)x - 3 + 3y + (27/6)x + 3 = 0(27/6)x + y + 3 = 0
Which type of lines pass through points (-27) (36) and (42) (91)?
Points: (-2, 7) and (3, 6) the slope is -1/5 Points: (4, 2) and (9, 1) the slope is -1/5 Both slopes are the same and so therefore they are parallel lines
What is the equation of the line containing the points (0, 0), (-3, -9), and (9, 27)?
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x
What is the slope of the line that contains the points -27 and 23?
If you mean points (x,y) : (-2, 7) and (2, 3) then the slope works out as -1 as the slope = (y2-y1)/(x2-x1) = (3-7)/(2 +2) = -4/4 = -1
