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Each of its 6 sides is 13 inches in length because 6*13 = 78 inches which is its perimeter

Q: What is the measure of a regular hexagon with primeter of 78 inches?

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The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.

The area is about 127.3 square inches.

s = 8 and a = 1.3 are not compatible for a regular hexagon.

If it is a regular 6 sided hexagon then its perimeter is 6 times 12 = 72 inches

Length of one side = 114/6 inches = 19 inches

Related questions

Perimeter of regular 6 sided hexagon: 6*7 = 42 inches

The question cannot be answered. A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular. And, since the hexagon is irregular, there is not enough information to answer the question.

Each side is 8 inches.

what is the area of a regular hexagon with sides lengths of 12 inches long

The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.

We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.

9 inches

The area is about 127.3 square inches.

The term hexagon means a six sided regular polygon; it is a shape, not a size. It can be any number of inches you like.

It is 374.12 sq inches.

s = 8 and a = 1.3 are not compatible for a regular hexagon.

See if the Hexagon is regular, that is, if all the sides are equal then the perimeter is 12inches x 6 as there are 6 sides for an hexagon. Therfore the answer is 72 inches.