what is the area of a regular hexagon with sides lengths of 12 inches long
A regular hexagon has six sides. You simply multiply the side length by six: 13 x 6 = 78
For a regular hexagon it is: area_regular_hexagon = 3/2 × √3 × side_length²
The radius of a circle inscribed in a regular hexagon equals the length of one side of the hexagon.
measure i side and times it times 6 * * * * * That only works with a regular hexagon and that cannot be assumed. You need to measure each of the six sides and sum the measures.
Each side of a regular hexagon is the same as its radius - in this case 31 inches.
The area of a regular hexagon with side lengths of 8cm is about 166.3cm2
The area of a regular hexagon with side lengths of 10 units is about 259.8 units2
It is a regular hexagon.
The area of a regular hexagon with side length of 20cm is about 1039.23cm2
Side length x 6 = perimeter
A regular hexagon has six sides. You simply multiply the side length by six: 13 x 6 = 78
Only if all the angles and side lengths are the same.
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
The area is about 41.57cm2
A hexagon cannot have a sum. There can be the sum of its interior angles, its exterior angles, its side lengths, its area (and that of some other area), or other characteristics, but not of a hexagon.
This cannot be answered without any given side lengths, since the interior angles of an irregular hexagon are different. Only the angles of a regular hexagon can be found without side lengths, and that is 120 degrees per angle.