The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
The area is about 127.3 square inches.
s = 8 and a = 1.3 are not compatible for a regular hexagon.
If it is a regular 6 sided hexagon then its perimeter is 6 times 12 = 72 inches
Length of one side = 114/6 inches = 19 inches
Perimeter of regular 6 sided hexagon: 6*7 = 42 inches
The question cannot be answered. A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular. And, since the hexagon is irregular, there is not enough information to answer the question.
Each side is 8 inches.
We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.
what is the area of a regular hexagon with sides lengths of 12 inches long
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
9 inches
The term hexagon means a six sided regular polygon; it is a shape, not a size. It can be any number of inches you like.
The area is about 127.3 square inches.
It is 374.12 sq inches.
s = 8 and a = 1.3 are not compatible for a regular hexagon.
See if the Hexagon is regular, that is, if all the sides are equal then the perimeter is 12inches x 6 as there are 6 sides for an hexagon. Therfore the answer is 72 inches.