0
What else can I help you with?
What is the perpendicular bisector equation of the line segment whose end points are at 3 5 and 7 7?
End points: (3, 5) and (7, 7) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Perpendicular bisector equation: y-6 = -2(x-5) => y = -2x+16
Gr equals 16 Br equals 8 and B is between G and R Is B the midpoint of segment Gr?
Yes, because GB = GR - RB
Midpoint of 16 and 21?
To find the midpoint of 16 and 21, you add the two numbers together and divide by 2. So, (16 + 21) / 2 = 37 / 2 = 18.5. Therefore, the midpoint is 18.5.
What is the midpoint between 6 6 and 16 -6?
Midpoint = (6+16)/2 and (6-6)/2 = (11, 0)
What is the perpendicular bisector equation passing through the line segment of 7 7 and 3 5 giving brief details?
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
What is the midpoint of the line segment with endpoints 16 5 and -6 -9?
If you mean endpoints of (16, 5) and (-6, -9) then its midpoint is (5, -2)
What is the perpendicular bisector equation of the line segment whose end points are at 3 5 and 7 7?
End points: (3, 5) and (7, 7) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Perpendicular bisector equation: y-6 = -2(x-5) => y = -2x+16
Is line segment AB the same as line segment BA?
Yes, while naming a line segment, as long as the two points are on the line, it does not matter what order they are in or which points they are. well their not
What is the class midpoint?
midpoint between 4-16
The class midpoint is?
midpoint between 4-16
Gr equals 16 Br equals 8 and B is between G and R Is B the midpoint of segment Gr?
Yes, because GB = GR - RB
Midpoint of 16 and 21?
To find the midpoint of 16 and 21, you add the two numbers together and divide by 2. So, (16 + 21) / 2 = 37 / 2 = 18.5. Therefore, the midpoint is 18.5.
What is the midpoint between 6 6 and 16 -6?
Midpoint = (6+16)/2 and (6-6)/2 = (11, 0)
What is the midpoint of the class 16-19?
17.5
How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
What is the equation and its distance from origin that meets the line joining the points 13 17 and 19 23 at its midpoint on the Cartesian plane showing work?
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
What is the perpendicular bisector equation passing through the line segment of 7 7 and 3 5 giving brief details?
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
