There is no mode because no number appears more than once.
79
72 73 79 75 76 81 81 85 88
(79, 81, 82, 91, 93, 95, 95) The mean is 88 The mode is 95 The median is 91
The range is 52. Is this your homework?
83
The mean average is 51
For the set (87 81 75 75 75 70 62 62 62 62 62 56 56): The mean is 68.076923 repeating The median is 62 The mode is 62
The variance of 73 72 67 74 78 84 79 71 76 76 79 81 75 80 78 76 78 = 16.8456
81
median is 79. Write in order; median is middle number: {72, 89, 67, 81, 75, 79, 81, 80, 62, 64, 83} → {62, 64, 67, 72, 75, 79, 80, 81, 81, 83, 89} To find middle number, count the number of data items, add 1 and divide by 2. If this is a whole number, that is the data item which is the median; if it is a fraction, take the mean average of the data items of the positions either side of the fraction (eg if the fraction is 3.5, take the mean average of the 3rd and 4th data items) There are 11 data items → median is (11+1)/2 = 6th data item → median is 79
79-Br is more common because its abudance is 50.69%. 81-Br's abudance is 49.31% making it less common. Abudance is the rate at which the isotope is found in nature. In this case out of every 100 Bromine atoms you found 51 would be 79-Br and 41 would be 81-Br.
meanAdd up the numbers and divide by how many there are: 87+75+89+81+90+73+85+96+65+92+78+79+83+85+79+90+86+72+74+88+81+85 = 1813There are 22 numbers.⇒ mean = 1813 ÷ 22= 829/22≈ 82.41medianSort the numbers into order; the median is the middle number (if an odd number of numbers) or the mean of the middle two (if an even number of numbers): Sorted: 65, 72, 73, 74, 75, 78, 79, 79, 81, 81, 83, 85, 85, 85, 86, 87, 88, 89, 90, 90, 92, 96There are 22, so the median is the mean of the middle two which are the 11th (83) and 12th (85) numbers:⇒ median = (83+85) ÷2= 84modeThe number which appears the most often. Having sorted the list for the median, it can be seen that the one with the highest frequency appears three times: ⇒ mode = 85