87+75+89+81+90+73+85+96+65+92+78+79+83+85+79+90+86+72+74+88+81+85 = 1813
There are 22 numbers.
⇒ mean = 1813 ÷ 22
= 829/22
≈ 82.41
Sorted: 65, 72, 73, 74, 75, 78, 79, 79, 81, 81, 83, 85, 85, 85, 86, 87, 88, 89, 90, 90, 92, 96
There are 22, so the median is the mean of the middle two which are the 11th (83) and 12th (85) numbers:
⇒ median = (83+85) ÷2
= 84
⇒ mode = 85
Mean is the average: Add all the numbers in a set and divide by the number of numbers. Median is if you wrote the numbers from largest to smallest, it would be the middle number. Mode is the Most common number.
Mean: 4.25 Median: 4 Mode: 4
1,2,2,2,3
who discovered mean median and mode
the mean is when you add the numbers and divide the answer by how many numbers is in the problem, the median is when you arrange the numbers from smallest to largest or from largest to smallest and find the middle number and the mode is how many times a number repeats itself.
The mean is 6.6. The median is 6. There is no mode.
the median and mode are but the mean is not
mean = 270 divided by 5 = 54 median = 45 mode = 45
What is the answer
Mean, median and mode are averages of sets of numbers, not one single one.
The mean and the median of the two numbers, 12107 and 1115 are 6611.There is no mode. The range is 10992.
mean: 104.4 median: 104 mode: 104 range: 5
range
Mean is the average: Add all the numbers in a set and divide by the number of numbers. Median is if you wrote the numbers from largest to smallest, it would be the middle number. Mode is the Most common number.
(10,10,30,30,30,50,50) (20,20,30,30,30,40,40) These two sets have the same mean, median and mode.
Mean, median and mode are ways to find averages. The mode is the most common answer in a set of data. The median the number that is in the middle when the numbers are put in order. The mean is the statical average.
Prior to the introduction of 170, the mean, median, mode and range did not exist since there were no numbers at all. Once 170 is introduced, it becomes the mean, median and mode. The range is zero.