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Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation.

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Q: What is the negative root in the equation x2 x 2 0?
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What is the solution set to the equation x2 plus 4 equals 0?

There are no real solutions to this equation because you cannot take the square root of a negative number. However,x2 + 4 = 0x2 = -4sqrt(x2) = sqrt(-4)x = 2i, -2ihere are the imaginary solutions.


Is it possible to have a square root as a solution to a quadratic equation?

Yes. For example, the equation x2 = 2, which in standard form is x2 - 2 = 0, has the two solutions x = square root of 2, and x = minus square root of 2.


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x2 + 3x + 3 = 0 doesn't factor neatly. Applying the quadratic formula we find two imaginary solutions: (-3 plus or minus the square root of -3) divided by 2x = -1.5 + 0.8660254037844386ix = -1.5 - 0.8660254037844386iwhere i is the square root of negative 1


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Which equation has the solution set 1 and 3?

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X2 plus 11x plus 11 equals 7x plus 9?

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What is the solution to the following equation x2 plus 3x plus 7 equals 0?

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