tn = n2 + 7
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
5, 11, 17, 23, 29
It is 4n -1 and so the next term will be 23
7, 11, (16), 18, 23. The median is 16 (shown in brackets).
It is 6n+5 and so the next term will be 35
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
5, 11, 17, 23, 29
It is 4n -1 and so the next term will be 23
7, 11, (16), 18, 23. The median is 16 (shown in brackets).
3n(n+1] + 5 is the nth term
The nth term is 7n-5 and so the 6th term will be 37
It is 6n+5 and so the next term will be 35
t(n) = 6*n - 1 where n = 1, 2, 3, ...
n + 6 * * * * * I suggest you try t(n) = 6n + 5 instead.
If you're asking what the nineth erm is, it's 58. The pattern is to add 7 to a umber to get the next number. 2+7=9, 9+7=16, 16+7=23, and so on.
Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...
9 ,16 ,23, 30 We note that there is a difference of '7' between terms. So the first part of the 'nth' term is 7n. Note the '7' becomes multiple. Next we need to find the constant 'c' So taking the first term (n = 1) we write. 7n + c = 9 7(1) + c = 9 7 + c = 9 c = 2 So the 'nth' term is '7n + 2' To verify , try the 3rd term n= 3 then answer should be '23'. 7(3) + 2 = 21 + 2 = 23 As required.