35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
5, 11, 17, 23, 29
n + 6 * * * * * I suggest you try t(n) = 6n + 5 instead.
It is: 27-2n
It is 4n -1 and so the next term will be 23
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
5, 11, 17, 23, 29
t(n) = 6*n - 1 where n = 1, 2, 3, ...
n + 6 * * * * * I suggest you try t(n) = 6n + 5 instead.
It is: 27-2n
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
3n(n+1] + 5 is the nth term
It is 4n -1 and so the next term will be 23
23-2nthis guy has a great way of explaining it, so look at his...What_is_the_nth_term_for_3_7_11_15_19
This appears to be a declining arithmetic series. If it is, the next term is 5, because each term is 3 less than the preceding term.=================================The 'N'th term is: [ 23 - 3N ].
Well, darling, it looks like we're dealing with a sequence where each number is increasing by a prime number. The nth formula for this sequence would be n^2 + n + 7. So, if you plug in n=1, you get 8; n=2 gives you 11; n=3 spits out 16; and so on. Keep it sassy and stay fabulous, my friend!
If you meant: 2 12 22 32 then the nth term = 10n-8