To find the nth term formula of a sequence, we first need to determine the pattern or rule that governs the sequence. In this case, the sequence appears to be increasing by adding consecutive odd numbers: 3, 5, 7, 9, 11, and so on. Therefore, the nth term formula for this sequence is given by the formula: nth term = 5n + 3.
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
5, 11, 17, 23, 29
It is 4n -1 and so the next term will be 23
7, 11, (16), 18, 23. The median is 16 (shown in brackets).
It is 6n+5 and so the next term will be 35
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
5, 11, 17, 23, 29
It is 4n -1 and so the next term will be 23
7, 11, (16), 18, 23. The median is 16 (shown in brackets).
3n(n+1] + 5 is the nth term
The nth term is 7n-5 and so the 6th term will be 37
It is 6n+5 and so the next term will be 35
t(n) = 6*n - 1 where n = 1, 2, 3, ...
n + 6 * * * * * I suggest you try t(n) = 6n + 5 instead.
If you're asking what the nineth erm is, it's 58. The pattern is to add 7 to a umber to get the next number. 2+7=9, 9+7=16, 16+7=23, and so on.
Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...