If you're asking what the nineth erm is, it's 58. The pattern is to add 7 to a umber to get the next number. 2+7=9, 9+7=16, 16+7=23, and so on.
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
2n +29
t(n) = 5 - 7n for n = 1, 2, 3, ... The difference between each term is -7, therefore the nth term will be: t(n) = -2 + -7 × (n - 1) = -2 + 7n + 7 = 5 - 7n
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The nth term is 7n-5 and so the 6th term will be 37
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The sequence given is -2, -9, -16, -23, -30. This is an arithmetic sequence where each term decreases by 7. The first term (a) is -2, and the common difference (d) is -7. The nth term can be expressed as ( a_n = -2 + (n-1)(-7) = -2 - 7(n-1) = -7n + 5 ).
9 ,16 ,23, 30 We note that there is a difference of '7' between terms. So the first part of the 'nth' term is 7n. Note the '7' becomes multiple. Next we need to find the constant 'c' So taking the first term (n = 1) we write. 7n + c = 9 7(1) + c = 9 7 + c = 9 c = 2 So the 'nth' term is '7n + 2' To verify , try the 3rd term n= 3 then answer should be '23'. 7(3) + 2 = 21 + 2 = 23 As required.
If you meant: 2 12 22 32 then the nth term = 10n-8
14+9n
2n +29
Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...
t(n) = 5 - 7n for n = 1, 2, 3, ... The difference between each term is -7, therefore the nth term will be: t(n) = -2 + -7 × (n - 1) = -2 + 7n + 7 = 5 - 7n
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].