Q: What is the nth term for 18 12 6 0 -6?

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24 - 6n

18 - 6n

x2-4=n

16 - 4nor4 (4 - n)

0,3,8,15,24,27,32,41

If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number

This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term

7 - 4n where n denotes the nth term and n starting with 0

This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.

Sn = 1 Sn = S(n-1)+12*(n-1), where S-0 (the first term) = 1 *This only works for stellar numbers of base 6

n-9+3

An = 2(n - 1)2 + 2(n - 1) = 2n(n - 1)

if ((18-18)/(12-14))**0.5 = 0 if (18-(18/12)-14)**0.5 = 1.58113883 if (18-18/(12-14))**0.5 = 3 if ((18-18)/12-14)**0.5 = 0

n - 1

(12 + 18 + 0) / 3 = 30/3 = 10

The nth term is 2n2. (One way to find that is to notice at all the numbers are even, then divide them by 2. The sequence becomes 1, 4, 9, 16, 25, which are the square numbers in order.)

12 and a halfpigs earmonkey buisnessthese really shouldnt be publicoinkrabbit rabiitwoof woofneigh

t(n) = n(n - 3)

6-3x+12=0 6+12-3x=0 18-3x=0 18=3x x=6

(n2+n+2) / 2, starting with n=0.

18 + 12 + 0 - 4 - 10 = 16

an^3 bn^2+cn+d=E(n) where E(n) is the value of the nth term and a,b, c and d are constants. So we have: a+b+c+d=1 8a+4b+2c+d=0 27a+9b+3c+d=3 64a+16b+4c+d=8 Then work it out from there. Assuming the first term was supposed to be -1 (minus 1) not 1 (plus one), then the nth term is given by: tn = n2 - 2n

0.6667

Range = Maximum - minimum = 18 - 0 = 18

According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. Conversely, it is possible to find a rule such that any number of your choice can be the next one.The simplest rule is un = 18 - 3n

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