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35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The given sequence is 1, 6, 13, 22, 33. To find the nth term, we can observe that the differences between consecutive terms are 5, 7, 9, and 11, which indicates that the sequence is quadratic. The nth term can be expressed as ( a_n = n^2 + n ), where ( a_n ) is the nth term of the sequence. Thus, the formula for the nth term is ( a_n = n^2 + n ).
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
The nth term is 18 -3n and so the next term will be 3
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
The nth term of the sequence is (n + 1)2 + 2.
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
In the study of sequences, given a number n, the position to term rule tells you how the nth term of the sequence is calculated.
n-9+3
The nth term of an AP with initial term a (= u{1}) and common difference d is given by: u{n} = a + (n - 1)d In this case: a = 6 d = (12 - 6) = 6 → u{n} = 6 + (n - 1)6 But this can be simplified: u{n} = 6 + (n - 1)6 = 6 + 6n - 6 = 6n
a + (n-1)d = last number where a is the first number d is the common difference.
t(n) = 3*n