tn=5n-3
It is: nth term = 35-9n
-11n + 17
The sequence goes up by 5 each time; the first term is two. So the nth term is 2 + 5n. n=50 => 2+50*5 = 252.
5, 8, 11, 14 and 17.
If you notice, there is a common difference between the terms: tn - tn-1 = -4 So the nth term is: tn = tn-1 - 4 For this recursive sequence to be defined though, you need something to start with as your tn-1. So start with t1= 3 and you're done.
The nth term is 5n-3 and so the next term will be 22
5
It is: nth term = 35-9n
-11n + 17
The nth term is 25-4n and so the next term will be 5
t(n) = 12*n + 5
7n - 4
I suspect that the first term should be "negative 3", ie the sequence is -3, 1, 5, 9, 13, 17, ... The nth term is 4n - 7
It is 4n+5 and so the next term will be 25
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
The nth term is: 3n+2 and so the next number will be 20
Just subtract 9.