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The differences between terms are 7,9,11,15

The differences of these differences are 2,2,2,2

Thus the formula for the sequence begins with n2

The sequence of numbers minus n2 is 5, 9, 13, 17, 21

The difference between the terms is 4

So the formula continues n2+4n

The sequence of numbers minus n2+4n is 1, 1, 1, 1, 1

So the formula for the nth term is n2+4n+1

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Q: What is the nth term formula for 6 13 22 33 46?

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The nth term is 3n+7 and so the next number will be 22

The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)

+9

x2-3=n

The nth term is 22n and so the next number will be 5*22 = 110

It is: nth term = 29-7n

The nth term is 5n-3 and so the next term will be 22

If you meant: 2 12 22 32 then the nth term = 10n-8

3n+1

t(n) = 6 + 8n

The nth term is -7n+29 and so the next term will be -6

Balls deep

The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.

5=22+12 8=22+22 13=22+32 20=22+42 29=22+52 40=22+62

the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps

6n+10

5n - 3

5

5n+2

It is: -6n+22

Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...

The nth term of an arithmetic sequence is given by. an = a + (n – 1)d. The number d is called the common difference because any two consecutive terms of an. arithmetic sequence differ by d, and it is found by subtracting any pair of terms an and. an+1.

You must mean what is the next number in the series, not the 'nth', which is undefined. The next number is 58.

tn=5n-3

1,7,13,19

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