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The differences between terms are 7,9,11,15

The differences of these differences are 2,2,2,2

Thus the formula for the sequence begins with n2

The sequence of numbers minus n2 is 5, 9, 13, 17, 21

The difference between the terms is 4

So the formula continues n2+4n

The sequence of numbers minus n2+4n is 1, 1, 1, 1, 1

So the formula for the nth term is n2+4n+1

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โˆ™ 2011-09-23 23:37:30
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Vinayak shukla

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โˆ™ 2020-11-27 19:32:21

6n+3 n(n+1)+n*(n+1)(2n+1)/6

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Anonymous

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โˆ™ 2020-08-11 01:16:53

n+n(n+1) (n+3) /6

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Q: What is the nth term formula for 6 13 22 33 46?
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Related questions

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