The differences between terms are 7,9,11,15
The differences of these differences are 2,2,2,2
Thus the formula for the sequence begins with n2
The sequence of numbers minus n2 is 5, 9, 13, 17, 21
The difference between the terms is 4
So the formula continues n2+4n
The sequence of numbers minus n2+4n is 1, 1, 1, 1, 1
So the formula for the nth term is n2+4n+1
6n+3 n(n+1)+n*(n+1)(2n+1)/6
n+n(n+1) (n+3) /6
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
The nth term is 3n+7 and so the next number will be 22
+9
3n+7
5=22+12 8=22+22 13=22+32 20=22+42 29=22+52 40=22+62
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
The nth term is 3n+7 and so the next number will be 22
+9
x2-3=n
3n+7
If you meant: 2 12 22 32 then the nth term = 10n-8
It is: nth term = 29-7n
5=22+12 8=22+22 13=22+32 20=22+42 29=22+52 40=22+62
t(n) = 6 + 8n
The nth term is 5n-3 and so the next term will be 22
the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps
The nth term is -7n+29 and so the next term will be -6