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Q: What is the nth term in 1 3 7 11 15?

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The next term is: 15+4 = 19 The nth term is: 4n-5

It is: nth term = 5-4n and so the next term will be -19

The nth term is 4n-1 and so the next term will be 19

The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.

2n + 1

It is: nth term = 29-7n

tn = 15 - 4n (n = 1,2,3, ... )

(2n-1)(-1)n

The nth term of the sequence is 2n + 1.

It is 4n -1 and so the next term will be 23

1...2....3....43...7...11..157 - 3 = 411 - 7 = 415 - 11 = 4(the start of the nth term is 4n)4 x 1 = 4(but the first term is 3, so...)4 -1 = 3nth term = 4n - 1

35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1

The nth term of the sequence is (n + 1)2 + 2.

The nth term is: 3n-7 and so the next number will be 11

The nth term is: 3n-7 and so the next number will be 11

Balls deep

The simplest, out of infinitely many possible answers, is the linear polynomial,U(n) = 4n - 1 for n = 1, 2, 3, ...

The nth term is -7n+29 and so the next term will be -6

5n+1

3n-2

This is an arithmetic sequence which starts at 14, a = 14, and with a common difference of -1, d = -1. We can use the nth term formula an = a + (n - 1)d to get an = 14 + (n - 1)(-1) = 14 - n + 1 = 15 - n.

2n+5

(n+1)2-1

One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1

It works out as -5 for each consecutive term