1...2....3....4
3...7...11..15
7 - 3 = 4
11 - 7 = 4
15 - 11 = 4
(the start of the nth term is 4n)
4 x 1 = 4
(but the first term is 3, so...)
4 -1 = 3
nth term = 4n - 1
The nth term in this sequence is 4n + 3.
The nth term of the sequence is 2n + 1.
3 11
The nth term of the sequence is (n + 1)2 + 2.
The 'n'th term is [ 4 - 3n ].
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
The nth term in this sequence is 4n + 3.
The nth term of the sequence is 2n + 1.
81
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
The nth term is 4n-1 and so the next term will be 19
3 11
The nth term of the sequence is (n + 1)2 + 2.
It works out as -5 for each consecutive term
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].