The nth term in this sequence is 4n + 3.
The nth term of the sequence is 2n + 1.
3 11
Tn = 10 + n2
The nth term of the sequence is (n + 1)2 + 2.
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
The nth term in this sequence is 4n + 3.
The nth term of the sequence is 2n + 1.
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
81
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
The nth term is 4n-1 and so the next term will be 19
3 11
Tn = 10 + n2
The nth term of the sequence is (n + 1)2 + 2.
To find the nth term of this sequence, we first need to determine the pattern or rule governing the sequence. By examining the differences between consecutive terms, we can see that the sequence is increasing by 9, 15, 21, 27, and so on. This indicates that the nth term is given by the formula n^2 + 1.
It works out as -5 for each consecutive term