1...2....3....4
3...7...11..15
7 - 3 = 4
11 - 7 = 4
15 - 11 = 4
(the start of the nth term is 4n)
4 x 1 = 4
(but the first term is 3, so...)
4 -1 = 3
nth term = 4n - 1
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The nth term in this sequence is 4n + 3.
The nth term of the sequence is 2n + 1.
The given sequence is an arithmetic sequence with a common difference of 7 (18-11=7, 25-18=7, and so on). To find the nth term of an arithmetic sequence, you can use the formula: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the position of the term, and d is the common difference. In this case, the first term a_1 is 11 and the common difference d is 7. So, the nth term of this sequence is 11 + (n-1)7, which simplifies to 11 + 7n - 7, or 7n + 4.
3 11
The nth term of the sequence is (n + 1)2 + 2.