The nth term of the sequence is 2n + 1.
11
1...2....3....43...7...11..157 - 3 = 411 - 7 = 415 - 11 = 4(the start of the nth term is 4n)4 x 1 = 4(but the first term is 3, so...)4 -1 = 3nth term = 4n - 1
The nth term in this sequence is 4n + 3.
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
The nth term of the sequence is 2n + 1.
It is: nth term = 5-4n and so the next term will be -19
The nth term is 4n-1 and so the next term will be 19
11
1...2....3....43...7...11..157 - 3 = 411 - 7 = 415 - 11 = 4(the start of the nth term is 4n)4 x 1 = 4(but the first term is 3, so...)4 -1 = 3nth term = 4n - 1
The nth term is: 5-2n
The nth term in this sequence is 4n + 3.
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
If you mean: 15 11 7 3 then the nth term is 19-4n
Un = (-1)n*(2n - 1)