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The answer is 128/(2^(n-1)) if the 1st term is 128. The divisor is found by the realization that these are decreasing powers of two.

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โˆ™ 2008-11-11 07:37:32
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Q: What is the nth term of 128 64 32 16.?
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If you mean: 2 4 8 16 32 64 it is 2^nth term and so the next number is 128


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1, 2, 4, 8, 16, 32, 64, 128


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