The answer is 128/(2^(n-1)) if the 1st term is 128. The divisor is found by the realization that these are decreasing powers of two.
The nth term is 2n2. (One way to find that is to notice at all the numbers are even, then divide them by 2. The sequence becomes 1, 4, 9, 16, 25, which are the square numbers in order.)
32, 60, 88, 116, 144
128 + 0 + 32 + 16 + 0 + 4 + 0 + 1 = 181
The LCM is: 128
It is: 128/4 = 32 and 32*32 = 1024 square cm
If you mean: 2 4 8 16 32 64 it is 2^nth term and so the next number is 128
The nth term in the sequence means an unspecified number an unspecified distance along the series. 8 16 32 64 128... n. It is also a shothand notation so the reader knows that the sequence continues.
2n
It goes up by (24-16) = 8 each time. The first time is 16. So the nth term is 8n + 8.
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The nth term is (36 - 4n)
The nth term is n2 + 4n.
the nth term for 1 2 4 8 16 32 is 2 to the power n-1. I cannot type superscript. It look like a big 2 and then n-1 where we put small number on the top right hand.
512 / 2 = 256 256 / 2 = 128 128 / 2 = 64 64 / 2 = 32 32 / 2 = 16 16 / 2 = 8 8 / 2 = 4 4 / 2 = 2 2 / 2 = 1
If you meant: 2 12 22 32 then the nth term = 10n-8
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
1/8 x 128 = 32/2 = 16