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If the sum of the interior angles of a polygon is 6840 how many sides does it have?
sum interior angles = (number of side - 2) × 180° → number of sides = sum interior angles ÷ 180° + 2 = 6840° ÷ 180° + 2 = 40 It has 40 sides.
What are the sum of the interior angles of a polygon with 40 sides?
The sum of the interior angles of a polygon can be calculated using the formula: [ \text{Sum of interior angles} = (n - 2) \times 180^\circ ] where (n) is the number of sides of the polygon. For a polygon with 40 sides ((n = 40)): [ \text{Sum of interior angles} = (40 - 2) \times 180^\circ = 38 \times 180^\circ = 6840^\circ ] Thus, the sum of the interior angles of a polygon with 40 sides is **6840 degrees Read more....tinyurl com/22enuvst
What is two angles whose sum adds to equal 180?
40 and 40
What is the sum of the measure of the exterior angles of a regular nonagon?
All exterior angles of any polygon sum to 360 deg. If there are 9 angles then each angle is 40 degrees.
Does a 40 sided polygon have 6840 diagonals?
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
Interior angles of a 40-gon?
The sum of the interior angles of an n-gon is (n-2)*180 degrees. So, for a 40-gon, the sum of the interior angles would be 38*180 = 6840 degrees. If the 40-gon was not regular that is as far as you could go. But if it was a regular n-gon, then all its interior angles are equal, and each would be of 6840/40 = 171 degrees.
What is the sum of measures of complementary angles?
Complementary angles are two angles that add up to 90 degrees. Example: 50 and 40 degrees
What is the sum of interior angles of a 40 sided polygon?
180*(40-2) = 180*38 = 6840 degrees.
One exterior angle of a regular polygon measures 40 What is the sum of the polygon's interior angle measures?
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.
What is the sum of the interior angles of a polygon with 40 sides?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 6840 degrees
One exterior angle of a regular polygon measures 40 degrees what is the sum of the polygons interior angle measure?
Sum of exterior angles = 360 degrees So there are 360/40 = 9 angles. Exterior angle = 40 deg so interior angle = 180 - 40 = 140 deg Nine angles, 140 deg each = 140*9 = 1260 degrees. Alternatively, once you know it is a nonagon (9-gon), sum of interior angles = (9-2)*180 = 7*180 = 1260 degrees.
One number is 4 times another number If their sum is 40 find the numbers.?
If your number is 4 times ?, and the sum is 40, your problem would be 40 divided by 4. You'd get 10.
