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It is 0.0794 moles.
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∙ 6y ago
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What is the number of moles in 32 grams of O2?
There are 1.0001 moles.
What is the empirical formula for 52.5 percent oxygen 25.4 percent phosphorus 22.1 percent aluminum?
Well first we assume a 100 g sample and then convert the elements into moles. We then divide them all by the number of moles that is the lowest of the 3. This procedure gives us AlPO4
How many moles of base are needed to neutralize 2 mol of acid for HNO3 plus KOH?
Since both the acid and the base have equivalent weights equal to their formula weights, 2 moles of KOH are needed to neutralize 2 moles of nitric acid.
Which factors must be constant Boyle's law?
n= no. of moles and t=temperature
How many banana are equal to 7.50 moles of banana?
Corvette Corvette 123;hahnysjejsgw
How many moles is 0.75g of Na2CO3?
The formula mass of sodium carbonate, Na2CO3 is 2(23.0) + 12.0 + 3(16.0) = 106.0Amount of Na2CO3 = mass of sample/molar mass = 0.75/106.0 = 0.00708mol There are 0.00708 moles of Na2CO3 in a 0.75g pure sample.
How many moles of Na2CO3 are there in 10.0 L of 2.0 M soluton?
Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------
Why was 1.06 g of Na2 CO3 added to 1 liter if water to prepare a 0.02 n solution?
Molarity = moles of solute/Liters of solutionSo, get moles sodium carbonate.1.06 grams Na2CO3 (1 mole Na2CO3/105.99 grams)0.0100009435 moles Na2CO3----------------------------nowMolarity = 0.0100009435 moles Na2CO3/1 Liter= 0.01 M Na2CO3==============ask your teacher why because that much sodium carbonate does not have 0.02 molarity
How many moles of ions are produced by the dissociation of 0.5 mol of Na2CO3?
1.5 moles
How many grams of NaOH are formed from reacting 120g sodium carbonate with excess calcium hydroxide?
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
How are 0.50 mol Na2CO3 and 0.50M Na2CO3 different?
0.5 mol of Na2CO2 is the ACTUAL dry crystal amount. 0.5 M 0f Na2CO3 means that o.5 moles has been dissolved in 1 litre of water. The M means ' moles per litre(dm^3)'.
How many moles of ions are produced when 2 mol of Na2CO3 dissociate?
Na2CO32 * 2 = 4 moles sodium.===========================
How many grams of carbon dioxide are produced when 7.5 grams of sodium carbonate reacts with nitric acid?
First write the balance equation: Na2CO3 + 2HNO3 ==> 2NaNO3 + CO2 + H2O Next calculate moles of Na2CO3 used: 7.5 g x 1 mole/106 g = 0.071 moles Na2CO3 Then look at mole ratio of Na2CO3 to CO2 and see that it is 1 to 1 Thus, moles CO2 produced = 0.071 moles Finally, convert moles CO2 to grams of CO2: 0.071 moles x 44g/mole = 3.1 g (to 2 significant figures)
How many moles of washing soda are there in 5g?
Washing soda is sodium carbonate, Na2CO3. Using the atomic weights from the periodic table and the subscripts in the formula, the molar mass of Na2CO3 = 106g/mol. 5g Na2CO3 x (1mol Na2CO3/106g/mol) = 0.05mol Na2CO3
How many grams of sodium carbonate is needed to react with 18.1 ml of 0.23M HCL?
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
What is the resulting concentration of Na When 70 milliliter of 3 molar Na2CO3 is added to 30 milliliters of 1 molar NaHCO3?
You have .07 Liters of 3 moles/Liter of Na2CO3. So if you do .07*3*2 (you multiply by two because there are TWO Na+ ions in Na2CO3) you get .42 moles of Na+. Then you do the same with NaHCO3. So, .03*1 is equal to .03 moles of Na+. Adding .42 with .03 will give you .45, the number of moles of Na+ of the whole solution. Since you are looking for concentration (which is moles if solute divided by Liters of solution), you must divide by .1 Liters (you get that by adding .07 and .03 of the two liquids that compose the solution) to get 4.5 Molar. That is the answer!
Convert the mass of Na2CO3 to moles with the molecular weight of 105.989?
the answer to your question is 0.0004 g/mol.
