There are 1.0001 moles.
Well first we assume a 100 g sample and then convert the elements into moles. We then divide them all by the number of moles that is the lowest of the 3. This procedure gives us AlPO4
Since both the acid and the base have equivalent weights equal to their formula weights, 2 moles of KOH are needed to neutralize 2 moles of nitric acid.
n= no. of moles and t=temperature
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Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------
The formula mass of sodium carbonate, Na2CO3 is 2(23.0) + 12.0 + 3(16.0) = 106.0Amount of Na2CO3 = mass of sample/molar mass = 0.75/106.0 = 0.00708mol There are 0.00708 moles of Na2CO3 in a 0.75g pure sample.
When Na2CO3 dissociates, it produces 3 moles of ions: 2 moles of Na+ ions and 1 mole of CO3^2- ions. So, if you have 0.5 moles of Na2CO3, you would produce 1.5 moles of ions in total.
To determine how many moles of Na2CO3 are used, you need to know the molar mass of Na2CO3. It is 105.99 g/mol. Then, you can calculate the number of moles using the given mass: mass in grams / molar mass = moles of Na2CO3.
To find the amount of sodium carbonate needed, first calculate the number of moles of HCl using its concentration and volume. Since the reaction between HCl and Na2CO3 is 1:1, the moles of Na2CO3 needed will be the same as HCl. Then, convert moles to grams using the molar mass of Na2CO3.
To calculate the number of moles of sodium carbonate in 212g, you need to first determine the molar mass of Na2CO3 (sodium carbonate). The molar mass of Na2CO3 is 105.99 g/mol. Then, you divide the given mass (212g) by the molar mass to find the number of moles (212g / 105.99 g/mol = 1.999 moles).
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of Na2CO3 (sodium carbonate) is 105.99 g/mol. So, to find the grams in 0.577 mol of Na2CO3, you would calculate 0.577 mol * 105.99 g/mol = approximately 60.98 grams of Na2CO3.
To convert the mass of Na2CO3 to moles, divide the given mass by the molecular weight of Na2CO3. If the given mass is in grams, simply divide the mass by the molecular weight to obtain moles.
The balanced chemical equation for this reaction is: Na2CO3 + Ca(OH)2 -> 2 NaOH + CaCO3 From the equation, we can see that 1 mole of sodium carbonate produces 2 moles of sodium hydroxide. Therefore, 120g of sodium carbonate would produce (120g / 105.99g/mol) * 2 moles of NaOH, which is about 2.27 moles. This corresponds to 2.27 moles * 40.00 g/mol ≈ 90.83 grams of NaOH.
The balanced chemical equation for this reaction is 2 HCl + Na2CO3 -> 2 NaCl + H2O + CO2. From the equation, 1 mole of Na2CO3 reacts with 2 moles of HCl. Calculate the number of moles of Na2CO3 in 4000g, then use the mole ratio to find the moles of HCl needed. Finally, convert moles of HCl to grams.
To find the moles of washing soda in 5g, you need to know its molar mass. Washing soda (Na2CO3) has a molar mass of approximately 105.99 g/mol. Using this, you can then calculate that there are approximately 0.047 moles of washing soda in 5g.
0.50 mol of Na2CO3 represents a fixed quantity of the compound (50% of a mole), whereas 0.50M Na2CO3 indicates the concentration of Na2CO3 in a solution (0.50 moles per liter). The former is a measure of the amount of the substance, while the latter is a measure of its concentration in solution.