answersLogoWhite

0


Best Answer

Well first we assume a 100 g sample and then convert the elements into moles. We then divide them all by the number of moles that is the lowest of the 3. This procedure gives us AlPO4

User Avatar

Wiki User

10y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the empirical formula for 52.5 percent oxygen 25.4 percent phosphorus 22.1 percent aluminum?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Basic Math

What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?

p2o5


75.7 percent arsenic and 24.3 percent oxygen what empirical formula would it have?

As2O3


What would the empirical formula be for 66 percent Barium and 34 percent Chlorine?

BaCl2


What is the empirical formula of a compound that is 4 percent sulfur and 6 percent oxygen by weight?

We can't tell. What's the other 90 percent? If you meant 40/60 instead... the mass of sulfur is twice that of oxygen, so a mass ratio of 40:60 is equivalent to an atom ratio of 1:3. The empirical formula would be SO3.


What is the molecular formula of fructose with C 40 percent H 6.72 percent O 53.28 percent?

We assume 100 grams and turn those percentages into grams and find moles of species. 40 grams carbon (1 mole C/12.01 grams) = 3.33 moles C 6.72 grams hydrogen (1 mole H/1.008 grams) = 6.67 moles H 53.28 grams oxygen (1 mole O/16 grams) = 3.33 The smallest mole number is 1, so we have two small numbers. Divide the large number by the small. 6.67/3/33 = 2 so.............. CH2O is the empirical formula. You did not state that you had a quantity of this compound ( such as 60 grams, or whatever ), so the molecular formula can not be found from this info. C6H12O6 is of course the molecular formula. To find the molecular formula you need a mass of the compound aside from the simple percentages. Then you find, as we have done, the empirical formula. you divide the mass given by the mass of the empirical formula and then take that quotient and multiply it times the empirical formula. In this case (CH2O) * 6 = C6H12O6, the molecular formula

Related questions

What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?

p2o5


Calculate the empirical formula of a compound formed from 3 percent C 0.3 percent H and 96.7 percent you Which formula below correctly represents the empirical formula?

Chi a+


Calculate the empirical formula of a compound formed from 3 percent c 3 percent h and 96 7 percent you which formula below correctly represents the empirical formula?

CHI3


What is the percent composition of phosphorus in AlBr?

- If you thought to the aluminum bromide (AlBr3) is a mistyped formula.- You may have shortened wrong "brass" and you thought to aluminium brass; the content of phosphorus is max. 0,01 %.


Can you determine the molecular formula of a substance from its percent composition?

Not completely. The empirical formula of a substance can be determined from its percent composition, but a determination of molecular weight is needed to decide which multiple of the empirical formula represents the molecular formula.


What is the empirical formula for a compound that is 43.6 percent and 56.4 percent oxygen?

P2o5


What is the empirical formula of 7.8 percent carbon and 92.2 percent chlorine?

CCl4


Explain why the percent composition of certain compounds are not sufficient to determine the compounds molecular formulas?

Because unlike the empirical formula, the molecular formula does not have to be the simplest ratio.If by chance you are given the percent composition of the elements in a substance, you could calculate the empirical formula and then the empirical formula's mass. However, the molecular formula equation is molecular formula= (empirical formula)n, where n is the mass of the molecular formula divided by the mass of the empirical formula. You would, therefore, need to know the mass belonging to the molecular formula, which you are not given.


If a compound containing chromium and silicon has 73.52 mass percent chromium what is its empirical formula?

Cr3Si2 is the empirical formula for a compound containing chromium and silicon an has 73.52 mass percent chromium.


75.7 percent arsenic and 24.3 percent oxygen what empirical formula would it have?

As2O3


What would the empirical formula be for 66 percent Barium and 34 percent Chlorine?

BaCl2


What is the empirical formula for 13 percent magnesium and 87 percent bromine?

mg br3