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Q: What is the number of subsets possible for the set in number 27?

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I believe the number of subsets for a set is equal to 2 raised to the power of the size of the set, so this set would have 27 = 128.

It has 27 = 128 subsets.

There are infinitely many subsets of real numbers. For example, {2, sqrt(27), -9.37} is one subset.

-27 is one possible answer.

Anything from zero to 26 .

This is not possible, 27 is an odd number, 4 odd numbers will always equal an even number.

It belongs to many many subsets including: {sqrt(13)}, The set of square roots of integers The set of square roots of primes The set of square roots of numbers between 12 and 27 {3, -9, sqrt(13)} The set of irrational numbers The set of real numbers

Think about it - this one is fairly simple. Ask yourself the question: "Does this set have a largest element?" If the answer is "yes", then the set is finite. If the answer is "no", the set is infinite. Note: This reasoning works for subsets of natural numbers; for integers, additional adjustments are needed.

No, 27 is not a prime number. 3x9 = 27

the number 27.

-9x = 27 x = -3 The solution set contains only one value for x, -3, which is just a point on the number line 3 units to the left of zero.

Each number is 3 times greater than the previous number

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