Yes, the square root of 2 is an irrational number.
The square root of 2 is 1.141..... is an irrational number
By root, I think you mean square root. The square root of 2 is approx. 1.414. The square root of 9 = 3, so this goes exactly at 3 on the number line. Square root 2 will be less than 1/2 way between 1 and 2 on the number line.
A square root of a number is a number that, multiplied by itself once, will equal the first number. Meanwhile a cube root of a number is a number that, multiplied by itself twice, will equal the first number. For example: the square root of 4 is 2. [ 2 X 2 = 4 ] [ 2 times itself equals 4 ] : the cube root of 8 is 2. [ 2 X 2 X 2 = 8 ] [ 2 times itself, and then times itself again, equals 4 ]
the square root of 2 is (an irrational number): 1.41421356....
(root 2)/3
2 is a prime number and its square root is an irrational number that cannot be expressed as a fraction
The answer is 16.If this number has the square root of 4 and the fourth root of 2 then this means that it is equal to 42 (4 * 4) and 24 (2 * 2 * 2 * 2).42 = 24 = 16.
Take the square root of the square root of the number (that is the fourth root of the number), for example: √√16 = √(√16) = √4 = 2 24 = 16 ⇒ 2 is the fourth root of 16.
there isn't. Square root of 2 can be approximated (1.41) but since it has an infinite number of decimal places then it is considered irrational. it therefore means that in algebra the square root of 2 is like a number in itself and can be written as 'root 2'.
No. Here are some counterexamples:The cubic root of 0 is 0.The cubic root of 1 is 1.The cubic root of 1/8 is 1/2.The cubic root of -8 is -2.In general, the cubic root of a number will be less than the original number,Â?if your number is greater than 1.
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