81
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
The number is 54. The sum of its digits is 5 + 4 = 9. 54/9 = 6.
the answer is 9
81 8+1=9 9*9=81
18. The sum of its digits is 9. And yes, it is unique.
45
Without digging too deeply into this question, we can see immediately that it has no solution. -- The largest possible sum of 3 digits is (9 + 9 + 9) = 27 -- 3 times (the largest possible sum of 3 digits) is (3 x 27) = 81 -- 3 times the largest possible sum of 3 digits is smaller than any 3-digit number.
The rule to decide if a number is divisible by 9 is to look at the sum of the digits. If the sum of the digits is divisible by 9, then so is the number.
The sum of the digits is also a multiple of 9. And, if the sum of the digits is too large, you can sum those digits and keep going.
18 1+8=9 9x2=18
let the no. be 9 square of 9=9*9=81 sum of the digits of square = 8+1=9 so if the no.=sum of the digits the it is a neon number
Yes it is. In order for it to be divisible by 9, the sum of the digits in the number must also be divisible by 9. In this case - the sum of the digits is 27.