The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
The sum of the digits is also a multiple of 9. And, if the sum of the digits is too large, you can sum those digits and keep going.
18 1+8=9 9x2=18
Yes it is. In order for it to be divisible by 9, the sum of the digits in the number must also be divisible by 9. In this case - the sum of the digits is 27.
If the sum of the digits of a given number equals nine or a multiple of nine, nine is a factor of that number.
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
The number is 54. The sum of its digits is 5 + 4 = 9. 54/9 = 6.
81
the answer is 9
18. The sum of its digits is 9. And yes, it is unique.
45
Without digging too deeply into this question, we can see immediately that it has no solution. -- The largest possible sum of 3 digits is (9 + 9 + 9) = 27 -- 3 times (the largest possible sum of 3 digits) is (3 x 27) = 81 -- 3 times the largest possible sum of 3 digits is smaller than any 3-digit number.
The rule to decide if a number is divisible by 9 is to look at the sum of the digits. If the sum of the digits is divisible by 9, then so is the number.
The sum of the digits is also a multiple of 9. And, if the sum of the digits is too large, you can sum those digits and keep going.
18 1+8=9 9x2=18
let the no. be 9 square of 9=9*9=81 sum of the digits of square = 8+1=9 so if the no.=sum of the digits the it is a neon number
A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.