It is 3.
3 to the fifth power, ie 243
the digit in the ones place is the 3
The answer depends on what the tens digit is greater than, and what the ones digit does then.
It is a 3. Look at the ones digit of successive powers of 7; this need only be done by considering the multiplication of the ones digit of the previous power of 7 by 7 (as this is the only calculation that affects the ones digit as each successive power of 7 is the previous power multiplied by 7) and taking the result modulus 10 (to extract the new ones digit as any excess over 9 is carried into the tens column): 7¹ → 7 mod 10 = 7 7² → (7×7) mod 10 = 9 7³ → (9×7) mod 10 = 3 7⁴ → (3×7) mod 10 = 1 7⁵ → (1×7) mod 10 = 7 At this point the pattern of the ones digit will obviously repeat the sequence of the four digits {7, 9, 3, 1}. To find the ones digit of any power of 7, take that power modulus 4 use that digit from the four digit sequence. Note that when taking the number modulus 4, the result will be in the range 0-3; when the result is 0, use the 4th digit from the sequence. 2015 mod 4 = 3 → the third digit of {7, 9, 3, 1}, which is 3, will be the ones digit of 7²⁰¹⁵.
The number is 949.
That means multiply it by 2. If your tens digit is 3, your ones digit is 6.
3
how you write out 3 to the fifth power is you have to use exponent's example:2x2x2x2x2 that's 2 to the fifth power
3
216.
There is a lot of answer for this, but I tell you one. The answer is 6541.