2x + 5y = 2 ..... Eq.1
-3x - y = -3 ..... Eq.2 .... we can write it in another form y = 3 - 3x
Put the value of y in Eq.1 the result will be :
2x + 5(3 - 3x) = 2
2x + 15 - 15x = 2
2x - 15x + 15 = 2
-13x + 15 = 2
-13x = 2 - 15
-13x = -13
x = -13/-13 ......... X = 1
to find Y, put the value of X in Eq.2
y = 3 - 3x
y = 3 - 3(1)
y = 3 - 3 .......... Y = Zero
(x + 6y)(x - 3y)
M=3 because y+y+y= 3xY and MY= MxY
5x + 8xy + 10x + 3xy = 15x + 11xycombine like terms (the x's and the xy's)
yes 3xy=6
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
no
No, it is not.
(x + 6y)(x - 3y)
M=3 because y+y+y= 3xY and MY= MxY
That equals 2xy + 3y which factors to y(2x + 3)
18x3y5 + 9xy3 - 3xy = 3xy(6x2y4 + 3y2 - 1)
5x + 8xy + 10x + 3xy = 15x + 11xycombine like terms (the x's and the xy's)
3xy-4x + 15y-20 Sol: As there are no number are same. So -4x-3xy +15y-20 -------------------- -4x-3xy+15y-20
3xy + 3y2 = 3y (x + y)
yes 3xy=6
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
-1