3xy + 3y2 = 3y (x + y)
x2 + 8xy + 15y2 = (x + 3y) (x + 5y)
That equals 2xy + 3y which factors to y(2x + 3)
Reorder the terms: -5 + 42y + 27y2 Factor a trinomial. (-5 + -3y)(1 + -9y)
-3xy
(3y2)4*3y2*3y2*3y2*3y2 = 38*y16 = 6561y16
18x3y5 + 9xy3 - 3xy = 3xy(6x2y4 + 3y2 - 1)
x3+27y3 = (x+3y) · (x2-3xy+9y2)
(3x + 3y)(x + y) = 3(x + y)2
To factor the expression (3xy - x), first identify the common factor in both terms, which is (x). Factor out (x) to get (x(3y - 1)). Thus, the factored form of (3xy - x) is (x(3y - 1)).
y(3y^2 - 12y + 4)
(4y + 1)(3y + 2)
(3y - 5)(y + 5)
2x2 + 6xy = 2x (x + 3y)
x2 + 8xy + 15y2 = (x + 3y) (x + 5y)
(x + 3y)(x2 - 3xy + 9y2)
(x + 6y)(x - 3y)
Divide by 'x'; x2+xy/x = x(x+y)