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What is the pOH of a solution with OH-1.4 10-13?

12.85 is the pOH.


What is the pOH of a solution with OH- 1.410-13?

To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that [OH⁻] = 1.41 × 10⁻¹³, calculate the pOH: pOH = -log(1.41 × 10⁻¹³) ≈ 12.85. Therefore, the pOH of the solution is approximately 12.85.


What is the pOH of a solution with OH 1.4 10-13?

12.85


What is the pOH of a solution with OH- 1.4 x 10-13?

12.85


What is the pOH of a solution with [OH-] = 1.4 x 10-13?

12.85


What is the pOH of a solution with OH 1.4 10 13?

The pOH of a solution with an OH- concentration of 1.4 x 10^-13 M is 1.85. This is calculated by taking the negative logarithm of the OH- concentration, which is -log(1.4 x 10^-13) = 12.85, then subtracting it from 14 to find the pOH: 14 - 12.85 = 1.85.


What is the pH of 0.067 0 M KOH solution?

The pH of a 0.0670 M KOH solution can be calculated using the formula pH = 14 - pOH. Since KOH dissociates completely in water to produce OH- ions, the pOH can be found by taking the negative logarithm of the hydroxide ion concentration (0.0670 M in this case). Then, pH = 14 - pOH, allowing you to determine the solution's pH.


A solution has a pOH of 4.5 What is the hydroxide ion concentration of this solution?

The hydroxide ion concentration can be calculated using the formula: ( [\text{OH}^-] = 10^{-\text{pOH}} ). Plugging in 4.5 for pOH, we get ( [\text{OH}^-] = 10^{-4.5} = 3.16 \times 10^{-5} , \text{M} ).


How is the pH and poh of 0.1 M HCl?

For a 0.1 M HCl solution, all of the HCl molecules will dissociate into H+ and Cl- ions, resulting in a concentration of 0.1 M for H+ ions. Since pH = -log[H+], the pH of the solution is 1. The pOH can be calculated by subtracting the pH from 14, so the pOH would be 13.


How do you calculate OH- with a ph of 1.12?

To calculate the concentration of hydroxide ions (OH-) from a given pH value, you can use the formula: [OH-] = 10^(-pH). For a pH of 1.12, the concentration of hydroxide ions would be [OH-] = 10^(-1.12) = 0.079 moles per liter.


When was Alef Poh-ji born?

Alef Poh-ji was born on 1987-04-13.


What is molarity poh and pH of 4.50G of NaOH if diluted in up to 750 ml of H2O?

MW NaOH is 23+16+1 = 40. 4.5g in 750ml is 6.0g in 1L. Molarity is 6/40 = 0.15 OH- concentration is 0.15, pOH is -log100.15 = 0.82 H+ concentration is 10-14/0.15 = 6.67x10-13 pH is -log10 6.67x10-13 = 12.18