0
What is the perimeter if the length is 7 feet and the width is 4 feet?
Wiki User
∙ 12y ago
22 feet
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
The perimeter of a rectangle is 18 feet and the area of the rectangle is 20 square feetWhat is the length of the rectangle?
Length: 4; Width: 5 or Length: 5; Width: 4
What is the perimeter of a square with an area of 800?
Area = Legth x Width In a square, Length = Width Therefore Area = Length x Length (or Width x Width) Area = Length squared Length = Square Root of 800 Perimeter = 4 x length Perimeter = 4 x Square Root of 800 Perimeter = 113.14
How you can find the perimeter of a rectangle if you know its length and width?
The perimeter of a rectangle is given by the formula P=2(L+W), where L is length and W is width. An example is a rectangle with length of 4 feet and width of 2 feet. So the perimeter is given by 2(4+2) which equals 12. Think of perimeter like a fence around someone's property. It's basically the border of the rectangle. To find it all you have to do is add all the sides together. This means that you add the length + length + width + width. You add the lengths and widths together twice because there are 2 sides that are length and 2 sides that are width.
What is the area of a square if it has the perimeter of 28 feet?
All 4 sides of a square have equal length. If the perimeter is 28 ft, then the length of each side is 7 ft. In any rectangle, the area is (length) times (width). In the square, (length) times (width) is the same as (side squared). 72 = 49 square feet.
What is a 8 and 4 in rectangle in perimeter?
8 is length. 4 is width
What is the perimeter of a rectangle with 50 feet as the length and 4 feet as the width?
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
If a rectangle has a perimeter of 70 feet what is the 4 to 5 length to width ratio?
If the length to width ratio is 4 to 5 then the length to width ratio is 4 to 5no matter what the perimeter. If the perimeter is 70 feet then the sides are 15.555... and 19.444... feet respectively.
What is the perimeter of a rectangle with a length of 11 feet and width of 4 feet?
The perimeter is 30 feet for this rectangle.
What would the length be of a rectangle that length was six feet and width was 4 feet?
6 feet... area 24 perimeter 20
The perimeter of a rectangle is 18 feet and the area of the rectangle is 20 square feetWhat is the length of the rectangle?
Length: 4; Width: 5 or Length: 5; Width: 4
What is the perimeter of a square with an area of 800?
Area = Legth x Width In a square, Length = Width Therefore Area = Length x Length (or Width x Width) Area = Length squared Length = Square Root of 800 Perimeter = 4 x length Perimeter = 4 x Square Root of 800 Perimeter = 113.14
The perimeter of a rectangular garden is 52 feet the length of the garden is 4 feet less than twice the width?
Let the width be x, so the length is 2x - 4. Since one half of the perimeter is 26 feet ( 52/2), then we have:x + (2x - 4) = 263x - 4 = 263x - 4 + 4 = 26 + 43x = 303x/3 = 30/3x = 102x - 4 = 2(10) - 4 = 20 - 4 = 16Thus the width of the rectangular garden is 10 feet, and the length is 16 feet.
If perimeter of a rectangle is 36 feet and its 4 feet wide What is the area?
Perimeter = 2*(Length+Width) So 36 = 2*(L+4) 18 = L+4 or L = 14
How you can find the perimeter of a rectangle if you know its length and width?
The perimeter of a rectangle is given by the formula P=2(L+W), where L is length and W is width. An example is a rectangle with length of 4 feet and width of 2 feet. So the perimeter is given by 2(4+2) which equals 12. Think of perimeter like a fence around someone's property. It's basically the border of the rectangle. To find it all you have to do is add all the sides together. This means that you add the length + length + width + width. You add the lengths and widths together twice because there are 2 sides that are length and 2 sides that are width.
The perimeter of a table is 24 ft the table is twice as long as it is wide what is the table's width?
Assuming the table's surface is a rectangle, the width is 4 feet. The length is 8 feet. The perimeter is therefore (4 + 8) x 2 = 24 feet.
What is the width of a rectangle with a perimeter of 70 feet if its length is 2 feet?
Perimeter = l + l + w + w, where l is the length and w is the width.P = 2l + 2wIn this case: 70 = 2(2) + 2w70 = 4 + 2w66 = 2ww = 33So the width of the rectangle is 33 feet.
How can the perimeter and width of a square be linked?
If the width is s units of length, then the perimeter is 4*s units.
