10
That depends on the dimensions !... A 1 x 18 rectangle has a perimeter of 38 ! A 2 x 9 rectangle has a perimeter of 22 ! A 3 x 6 rectangle has a perimeter of 18 !
A rectangle 10.5 x 3 will have a perimeter of 27 in.
The perimeter of a 12 cm x 3 cm rectangle is 2*(12+3) cm = 2*15 cm = 30 cm.The perimeter of a 12 cm x 3 cm rectangle is 2*(12+3) cm = 2*15 cm = 30 cm.The perimeter of a 12 cm x 3 cm rectangle is 2*(12+3) cm = 2*15 cm = 30 cm.The perimeter of a 12 cm x 3 cm rectangle is 2*(12+3) cm = 2*15 cm = 30 cm.
No. A rectangle of 1 x 3 has the same perimeter as a rectangle of 2 x 2, but the areas are different.
The perimeter of a rectangle is calculated by adding all four sides together. In this case, the length is 12m and the width is 3m. The formula for the perimeter of a rectangle is P = 2(length) + 2(width). Therefore, the perimeter of this rectangle would be P = 2(12m) + 2(3m) = 24m + 6m = 30 meters.
2*16+2*3= 38
To find the perimeter of a polygon, just add the length of all the sides. In this case, the four sides of the rectangle.
You can make a perimeter with side lengths if 3, 3, 3, 3 or you could do a rectangle with side lengths of 4, 4, 2, 2. Finally you could do a rectangle with side lengths of 5, 5, 1, 1.
To calculate the perimeter of a rectangle, you multiply 2 x length and add 2 x width. So the perimeter of a 3 x 5 rectangle would be: 2 x L + 2 x W (2 x 3) + (2 x 5) 6 + 10 = 16
the perimeter of a rectangle is calculated by : 2*(l+b)
You cannot find the perimeter unless the rectangle is a regular rectangle (a square) in which case the perimeter is 4 times the square root of the area. With just the area the shape of the rectangle could be any number of shapes with different perimeter, for example, imagine 6 square units 1cm by 1cm arranged in a 1*6 configuration to give a long thin rectangle, the perimeter would be 6+6+1+1=14cm, the same 6 arranged in a 3*2 rectangle would have the same area, but a perimeter of 3+3+2+2=10cm, for this reason a rectangle's perimeter cannot be determined from the area alone.
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.