0
What else can I help you with?
What is the perimeter of a square field that has an area of 10 000 m squared?
If the length of the sides is x metres then area = x2 ie x2 = 10000 so that x = 100 metres Then perimeter = 4*x = 400 metres.
What is the relationship between the perimeter of a figure and the perimeter of a figure when the length and width are doubled?
x2=y
A square may have the same numerical value for its area and perimeter?
Let's say the side length of a square is x. The square's area is just x2, and its perimeter is 4x. If we want the perimeter to be equal to the area, 4x = x2, so x = 4.
How do you find the perimeter of a square when the diagonal is 32 feet?
Let's call x the unknown side of the square. Using Pythagoras's theorem: x2+x2 = 322 x2+x2 = 1024 2x2 = 1024 x2 = 512 x = 22.627417 feet So the square has 4 sides of 22.627417 feet Perimeter = 4*22.627417 = 90.50966799 feet
Would you show that the area of a square can equal its perimeter?
Let the area be x2 and the perimeter be 4x: x2 = 4x x2-4x = 0 x(x-4) = 0 x = 0 or x = 4 So: 42 = 4*4 which is the same as 16 = 16 But remember that the area is in square units while the perimeter is in linear units.
How do you find the distance around a figure?
To find the distance around a figure, you calculate the perimeter. The perimeter is the total distance around the outside of a shape or figure. To find the perimeter of a rectangle or square, you add up all the sides. For a circle, you can find the perimeter by multiplying the diameter by π (pi).
How many solutions to x2-10 equals 0?
x2-10 = 0 x2 = 10 x = the square root of 10
How do you do x2 equals 11x -10?
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
What are the factors of x2 equals -11x-10?
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
X2 equals 11x - 10?
x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}
What is the perimeter of 12x15 foot room?
(12+15)x2 = 27x2 = 54 feet
X2 plus 7x plus 10 equals?
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
