x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}
21
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
5x + 32 = 11x - 105x - 11x = -10 - 32-6x = -42x = 7
12x = 11x - 5, subtract both sides by 11x x = -5
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}
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X2 -11x +10=(x - 1 )(x - 10)
572 Because 2x11=22 and 13x2=26 and 22x26=572.
It doesn't factor evenly if it were x**2-11x+10: x**2-11x+10 = (x-1)(x-10)
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
You take 11x10 then by 2...
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
The LCM is the absolute value of x.
X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2
5x + 32 = 11x - 105x - 11x = -10 - 32-6x = -42x = 7