Let the dimesions be x and y which have been squared and square both the diagonal and area:-
Pythagoras: x+y = 39.0625 => y = 39.0625-x
Area: xy = 351.5625 => x(39.0625-x) = 351.5625
So it follows: 39.0625x-xsquared-351.5625 = 0
Using the quadratic equation formula: x = 14.0625 and x = 25
Square root both numbers: x = 3.75 and x = 5
By substitution: x = 3.75 and y = 5
Perimeter: 2*(3.75+5) = 17.5 cm
Check for area: 3.75*5 = 18.75 square cm
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
Here is what you are supposed to do: * Convert to consistent units. For example, convert the cm to mm. * Write an equation for the diagonal (in terms of length and width). Replace the known diagonal. * Write an equation for the area, in terms of length and width. * Solve the two equations simultaneously. * Calculate the perimeter.
It works out as: 35 cm or 350 mm
Given a 56 cm diagonal, the square will have a perimeter of 158.4 cm
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
Square the diagonal and take away the square of width, this gives you the square of the other side. Add the square root of the two sides and multiply by two.
Here is what you are supposed to do: * Convert to consistent units. For example, convert the cm to mm. * Write an equation for the diagonal (in terms of length and width). Replace the known diagonal. * Write an equation for the area, in terms of length and width. * Solve the two equations simultaneously. * Calculate the perimeter.
Given a 56 cm diagonal, the square will have a perimeter of 158.4 cm
It works out as: 35 cm or 350 mm
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
The perimeter of a square with a diagonal of 12 centimeters is: 33.9 centimeters.In future, to find out the perimeter of a square when you only know it's diagonal, use Pythagoras or times the diagonal by 2.828427125.This number is irrational, and is like a pi for the diagonals of squares.I call it Tau.It is the relationship between the diagonal of all squares and there perimeter.
The perimeter of this square is 56.569 meters.
The perimeter of this square is 45.25 cm
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
40 meters.
yes