The diagonal works out as length of 33.3 cm or 333 mm
To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
6x-14
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
It works out as: 35 cm or 350 mm
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
You CAN'T calculate the perimeter of a rectangle, knowing only its diagonal. You do need some additional information about the rectangle - such as its width, or its length, or perhaps the length/width ratio.
The perimeter is 18 feet.
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.
It depends on what information you do have. The length and area, the length and diagonal, the length and perimeter, etc. Each set generates a different answer.
6x-14
The perimeter of a rectangle is not sufficient to determine its length.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
It works out as: 35 cm or 350 mm
It depends on whether you want the width as a fraction of the length or perimeter or something else - like the diagonal.
The diagonal is 7.21 feet.