82 inches.
The perimeter is 38.
The perimeter is 30 feet for this rectangle.
56
The width is 8 feet
Perimeter of a rectangle = 2 x (length + width) = 2 x (2 + 9) = 2 x 11 = 22 square inches.
Perimeter = 11+11+8+8 = 38 inches
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
Perimeter = 32 inches. Area = 55 square inches.
28
Length is 11 and width is 7 and so 11 times 7 = 77 square cm
Let the length be 2x and the width be x: 2(2x+x) = 66 4x+2x = 66 6x = 66 x = 11 feet length = 22 feet and width = 11 feet
11 ft. 11+11+6+6=34