The perimeter is 38.
The width is 8 feet
11 ft. 11+11+6+6=34
if the perimeter is 46m, then side + length = 23 so we need two values, when added together are 23, with a difference of 11 6 + 17 = 23, (and have a difference of 11) therefore the length = 17m, width = 6m
The rectangle is 99 cm2 in area. Here's how we got it. The rectangle has length (l) and width (w). A length and a length and a width and a width all added up equals 40 cm. And l is 2 cm longer than w, so l = w + 2. If we add w + 2 and w + 2 (the two lengths) and w and w, we get 40 cm. That's 4w + 4 cm = 40 cm. 4w = 36 cm, and w = 9 cm. The width is 9 cm, and the length is 2 cm more or 11 cm. The rectangle is 9 cm by 11 cm, and its area is 9 x 11 cm2, or 99 cm2.
perimeter = 2 * (length + width)= 2 * (11 + 4)= 2 * 15= 30 metresbasically 30 meters
56
The perimeter is 30 feet for this rectangle.
82 inches.
The width is 8 feet
Perimeter of a rectangle = 2 x (length + width) = 2 x (2 + 9) = 2 x 11 = 22 square inches.
Perimeter = 11+11+8+8 = 38 inches
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
Perimeter = 32 inches. Area = 55 square inches.
28
Length is 11 and width is 7 and so 11 times 7 = 77 square cm
Let the length be 2x and the width be x: 2(2x+x) = 66 4x+2x = 66 6x = 66 x = 11 feet length = 22 feet and width = 11 feet
11 ft. 11+11+6+6=34