The perimeter is 38.
The width is 8 feet
11 ft. 11+11+6+6=34
if the perimeter is 46m, then side + length = 23 so we need two values, when added together are 23, with a difference of 11 6 + 17 = 23, (and have a difference of 11) therefore the length = 17m, width = 6m
To find the area of a rectangle, you need to know the length and width. Let's denote the width as x cm. Since the length is 2 cm longer than the width, the length would be x + 2 cm. The perimeter of a rectangle is the sum of all its sides, which in this case is 2(width + length). So, we have 2(x + x + 2) = 40 cm. Solving this equation gives x = 8 cm. Therefore, the width is 8 cm and the length is 10 cm. The area of the rectangle is width * length, which is 8 cm * 10 cm = 80 cm².
perimeter = 2 * (length + width)= 2 * (11 + 4)= 2 * 15= 30 metresbasically 30 meters
56
The perimeter is 30 feet for this rectangle.
82 inches.
The width is 8 feet
Perimeter of a rectangle = 2 x (length + width) = 2 x (2 + 9) = 2 x 11 = 22 square inches.
Perimeter = 11+11+8+8 = 38 inches
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
Perimeter = 32 inches. Area = 55 square inches.
Length is 11 and width is 7 and so 11 times 7 = 77 square cm
Let the length be 2x and the width be x: 2(2x+x) = 66 4x+2x = 66 6x = 66 x = 11 feet length = 22 feet and width = 11 feet
11 ft. 11+11+6+6=34
30 ft. ************************ Method: (11×2)+(4×2) = 30ft