Length is 11 and width is 7 and so 11 times 7 = 77 square cm
Length = (Perimeter - twice width) / 2
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
The width of the rectangle would be 32.5 meters.
Length + width = half perimeter = 100". Length is 98", width is 2"
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the width equals 14 cm. and the length equals 31 cm.
21cm3
The perimeter of a rectangle is found by the following formula: (Length x 2) + (Width x 2) or Length + Length + Width + Width.
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle