It is 1, since k^1 = k.
racist
its k itself
It is a number such that, if 10 were raised to that power, the answer would be k. ie 10log k = k
Factor them. k2 = k x k k2 - 1 = (k - 1)(k + 1) k2 - 2k + 1 = (k - 1)(k - 1) Combine the factors, eliminating duplicates. k2(k + 1)(k - 1)(k - 1) = k5 - k4 - k3 + k2, the LCM
K = 6
If: k5 = 9765625 Then: k = 25
In the context-free grammar CFG, the variables i, j, and k represent the exponents of a, b, and c respectively in the generated strings. The variable i is equal to the sum of j and k. The grammar produces strings with a raised to the power of i, b raised to the power of j, and c raised to the power of k.
k would equal 8. you add the powers on one side of the equation together so you should end up with 7 to the power of 11 then you minus 7 to the power 3 from the opposite side of the equation leaving you with 7 to the power 8 equals 7 to the power k. you can then see that k is the equivalent of 8.
If the power of ten is k, where k is an integer thenif k < 0 then the decimal point moves k places to the left;if k = 0 then the decimal point does not move; andif k > 0 then the decimal point moves k places to the right.
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