If: k5 = 9765625
Then: k = 25
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2
Equation: x^2 +2kx +10x +k^2 +5 = 0 Using the discriminant: (2k +10)^2 -4*1*(k^2 +5) = 0 Multiplying out the brackets: 4k^2 +40K +100 -4k^2 -20 = 0 Collecting like terms: 40k +80 = 0 => 40k = -80 => k = -80/40 Therefore the value of k = -2
If you mean: kk-5 then it can be k^2-5 But if you mean: k+k-5 then it can be 2k-5
The vertex of this parabola is at -5 -2 When the x-value is -4 the y-value is 2. The coefficient of the squared expression in the parabola's equation is 4. y = a(x - h)2 + k; (h, k) = (-5, -2); (x, y) = (-4, 2) 2 = a[-4 -(-5)]2 - 2, add 2 to both sides 4 = a(-4 +5)2 4 = a(1)2 4 = a
It is: y-4 = 9(x-5) => y = 9x-41 Or as: 9x-y-41 = 0. Another version of the standard form of a linear equation in coordinates x and y is y = s x + k, where s is the slope and k is a constant. In this question, the slope s is directly given, as is the value of y at the point where x = 5 so that- 44. The slope is always the coefficient of x in this standard form, and the constant k can be determined by solving the equation for the coordinates of the given point: When x = 5, y = (9 X 5) + k, and y(5) is stated by the question to be 4. 9 X 5 equals 45; therefore to obtain the right value for k, 45 + k =4 or k = - 41. The standard form of the equation is therefore y = 5x - 41.
K= 18.666666
k = 5
first need to find the voltage value to calculate the Power Dissipation. Because P= I*V Here V = IR in given value I = 30 m A = 0.03 A R= 5 K Ohm = 5000 V= 0.03*5000=150 V= 150 V Power dissipation p= 150*0.03=4.5 Watt
The tile with the letter K is the only tile with a value of 5 points.
If ( y ) varies directly with ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given that ( y = 25 ) when ( x = 5 ), we can substitute these values into the equation: ( 25 = k \cdot 5 ). Solving for ( k ) gives us ( k = \frac{25}{5} = 5 ). Thus, the value of ( k ) is 5.
K=1
k can have any value; however, the range of values permitted depends upon different things: The value of k depends on the value of x (ie given a value of x, the value of k can be calculated so that kx² + 4x + 5 = 0 has a root at that value of x): kx² + 4x + 5 = 0 => kx² = - 4x - 5 = -(4x + 5) => k = -(4x + 5)/x² Note that if x = 0, then the value of k is not determinable. Another possible answer using the discriminant of b²-4ac; from this the number of roots of the equation can be discovered: Two real roots: b²-4ac > 0 → 4² - 4×k×5 > 0 → 16 - 20k > 0 → 20k < 16 → k < 4/5 So for all values of k less than 4/5 there are two real roots of the quadratic kx² +4x + 5 = 0 One real repeated root: b² - 4ac = 0 → k = 4/5 So for k = 4/5, the quadratic (4/5)x² +4x +5 = 0 (→ 4x² +20x + 25 = 0) has one repeated real root. Two complex roots: b² - 4ac < 0 → k > 4/5 So for all values of k greater than 4/5 there are two complex roots of the quadratic kx² +4x + 5 = 0
To find the value of k, you need to isolate k on one side of the equation. Start by adding 7 to both sides of the equation to get 5k = 0. Then, divide both sides by 5 to solve for k. Therefore, the value of k is 0.
To find the value of ( k ) for which ( 4K + 6 = 26 ) and ( 6k - 2 = 28 ), we can solve each equation. For ( 4K + 6 = 26 ): [ 4K = 20 ] [ K = 5 ] For ( 6k - 2 = 28 ): [ 6k = 30 ] [ k = 5 ] Both equations yield ( k = 5 ). Thus, when ( k = 5 ), both expressions have the same length.
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An equation for ( x - 5 ) can be expressed as ( x - 5 = 0 ). This equation states that ( x ) is equal to 5. Alternatively, you could also express it as ( x - 5 = k ), where ( k ) is any constant value.
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