It is a number such that, if 10 were raised to that power, the answer would be k.
ie 10log k = k
Chat with our AI personalities
y = c ekxpassing through (1, 180) and (3, 20).(Note: All of the 'log' in the following are natural logs.)log(y) = log(c) + k log(x)Log(180) = log(c) + k log(1) = log(c)c = 180log(20) = log(180) + k log(3)log(20) - log(180) = k log(3)k = log(20/180) / log(3) = - log(9) / log(3) = -2y = 180 e-2xIn checking my work, I find that this doesn't work at all.Oh woe! Where have I failed ?--------------------------------------------Here's what I did:y=Cekx which passes through the points (1,180) & (3,20)(1) Substitute the values of x & y to create two equations:180 = Cek & 20 = Ce3k(2) Rearrange in terms of the constant, C:C=180/ek & C=20/e3k(3) Since both sets of points satisfy the exponential function, the constant will be the same so:180/ek = 20/e3k(4) Now rearrange and solve for k:180e3k = 20ek9 = e(k-3k)ln(9) = ln(e-2k)ln(9) = -2kk = -ln(9)/2 which is approx. -1.09861(5) Now substitute k into one of the equations to solve for C:C =180/e(-1.09861)C = 539.9987 or rounded to 540So the exponential function that includeds the points (1,180) & (3,20) can be approximated as:y = 540ekx , where k = -1.09861
p;kp;k;ko;jk;
The graph of log base b(x-h)+k has the following characteristics. the line x = h is a vertical asymptote; the domain is x>h, and the range is all real numbers; if b>1, the graph moves up to the right. of 0>b>1, the the graph moves down to the right.
The K value of PVC resin is calculated using the Fikentscher K value equation, which is K = (135.5 - 0.31 * log(viscosity)) * (1 - 0.008 * (log(viscosity) - 1)), where viscosity is the intrinsic viscosity of the PVC resin solution. In practice, the viscosity is typically measured using an Ubbelohde viscometer or an Ostwald viscometer. The K value is an important parameter that indicates the average molecular weight of the PVC resin and is used to classify different grades of PVC based on their properties and applications.
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4