It is: 3^2 times 5^2 times 7^1 = 1575
32*52*7 = 1575
Factorization: 3*3*5*5*7
To find five numbers that multiply to 1575, you can use its prime factorization. The prime factorization of 1575 is (3^2 \times 5^2 \times 7). One possible combination of five numbers that results in 1575 is 3, 5, 5, 7, and 3, as (3 \times 3 \times 5 \times 5 \times 7 = 1575). Other combinations are also possible by rearranging these factors.
1575 Divide by three. 525,3 Divide by three. 175,3,3 Divide by five. 35,5,3,3 Divide by five. 7,5,5,3,3 Stop. 3 x 3 x 5 x 5 x 7 = 1575
To find the highest common factor (HCF) of 441 and 1575, we need to factorize both numbers. The prime factorization of 441 is 3^2 x 7^2, and the prime factorization of 1575 is 3^2 x 5^2 x 7. To find the HCF, we take the product of the common prime factors raised to the lowest power they appear in both factorizations, which is 3^2 x 7 = 63. Therefore, the highest common factor of 441 and 1575 is 63.
As a product of its prime factors: 3*3*5*5*7 = 1575
1575 = 32 x 52 x 7
1575 = 3 * 3 * 5 * 5 * 73 x 3 x 5 x 5 x 7 = 1575
As a product of its prime factors: 3*3*5*5*7 = 1575
Composite. A prime number is defined as "a number not divisable by any integer other than itself and 1". It can be seen that 1575 can be divided by 5,15,25,75 and maybe more. None of these numbers are 1575 or 1 so the number is composite.
No, 1575 is not a prime number, because it can be divided by numbers other than 1 and itself. In particular without much thought you can see that it is divisible by 5.
Since the number ends with 5, 5 is a factor. 3 is also a factor. Divide it by those factors, then see if you can find additional factors.