For the case where the disease is a recessive trait (more likely), the probability is 1/2 that they will carry the diseased gene but not show it. If the disease is a dominant trait, the probability is 1/2 that they will get it and show it. Having said that, in the recessive case, if both parents are carriers, then there is a 1/4 case the child will get it from both and then show the disease.
I have answered regarding genetically-transmitted diseases. Mental illness and other forms of "disease" will be different.
It is 0.48, approx.
The baby has a 50% chance of inheriting brown hair and a 50% chance of inheriting black hair from the parents. For eye color, the baby has a 75% chance of inheriting brown eyes and a 25% chance of inheriting light brown eyes, as determined by the parents' and mate's eye colors.
While the answer will vary according to country, parents ages and genetic make up, the global probability is 0.48, approx.
A coin flip can be used to the selection of alleles that leads to the genetic/physical makeup of offspring. Like a coin toss involves a 50/50 probability between heads & tails, the probability of offspring for inheriting either one of each parents alleles for each gene is also 50/50. Each parent has two alleles for each gene and passes one on to its offspring at random. The coin flip represents heredity. A baby's physical traits are produced based on probability determined by the traits of the parents. :-)
If you know nothing about the parents' risk for these diseases or other contributing factors (race, environment, etc.), then the answer depends solely on the probabilities of getting any one of those diseases. Let's say the risks are P1, P2 and P3 where P1 is the probability of the baby having rare disease #1 and so on. A probability of 1 is a sure thing and 0 means no chance, so the probability of a rare disease is a number slightly greater than 0. The risk of getting disease #1 AND #2 AND #3 is the product: P1xP2xP3. If, for example, the each risk is one in a million (P1=P2=P3=0.000001), then the odds of having a baby with all three is 1 in 1,000,000,000,000,000,000. The math changes severely if one of the parents is at risk for the disease. Let's say the mother has one gene that causes the disease #1. Then P1 is no longer 1 in a million, it is 0.5. If the parent's racial group is afflicted with P2=0.001 as well, then P=0.5x0.001x0.000001=0.000000005, which is 500,000 the risk of others.
Assuming coat color is determined by a single gene with black being dominant and brown being recessive, the probability of a heterozygous black coat (Bb) mom and brown coat (bb) dad having a brown coat baby (bb) is 50%. This is because each parent can pass on either the dominant black allele (B) or the recessive brown allele (b) to their offspring, resulting in a 50% chance of inheriting the brown allele from both parents.
Assuming that the probability of having a baby girl is 1/2 and that of having a baby boy is 1/2, the probability of having 3 baby girls in a row is (1/2)(1/2)(1/2)=1/8.
It depends on the genome of the parents. If the mother has red hair and freckles, the probability goes up. Also, if the man's white parent had red hair and freckles, the probability also goes up.
Punnet squares are used mainly by doctors to determine a baby's chances of inherating an trait of disease from it's parents.
Because the parents might choose to abort a baby that isn't of the preferred gender (if the parents wanted a boy they might abort a fetus that is a girl).
parents cant design their baby!
Target group for baby products - 1. Parents Excepting Baby 2. Parents with New Born Baby 3. Parents already Having Baby 4. Parents having baby of bigger age 5. Parents planning a baby (As some measurable should also be taken in such conditions).